3a^2-18a+4=5a^2+4

Solution for 3a^2-18a+4=5a^2+4 equation:

3a^2-18a+4=5a^2+4

We move all terms to the left:

3a^2-18a+4-(5a^2+4)=0

We get rid of parentheses

3a^2-5a^2-18a-4+4=0

We add all the numbers together, and all the variables

-2a^2-18a=0

a = -2; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·(-2)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*-2}=\frac{0}{-4}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*-2}=\frac{36}{-4}
=-9
$